Initially spring is relaxed & connected by a block. The system is free to oscillate in vertical plane. If elongation in spring at equilibrium is 'a' & elongation in spring when block stops for moment is 'b', find b - a.

8 cm

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6 cm

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4 cm

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2 cm

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Solution

The correct option is C 4 cm
$x_{e q b n} = \frac{m g}{k}$
Block stops for a moment, then $m g x = \frac{1}{2} k x^{2}$
$x_{m a x} = \frac{2 m g}{k}$
$b = 2 m g / k$
at equilibrium $x = \frac{m g}{k} = \frac{40}{1000} = 4 c m$ ,
$b - a = m g / k$

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Initially spring is relaxed & connected by a block. The system is free to oscillate in vertical plane. If elongation in spring at equilibrium is 'a' & elongation in spring when block stops for moment is 'b', find b - a.

The correct option is C 4 cmxeqbn=mgk Block stops for a moment, then mgx=12kx2 xmax=2mgk b=2mg/k at equilibrium x=mgk=401000=4 cm, b−a=mg/k

The correct option is C 4 cm
$x_{e q b n} = \frac{m g}{k}$
Block stops for a moment, then $m g x = \frac{1}{2} k x^{2}$
$x_{m a x} = \frac{2 m g}{k}$
$b = 2 m g / k$
at equilibrium $x = \frac{m g}{k} = \frac{40}{1000} = 4 c m$ ,
$b - a = m g / k$