Initially the circuit is in steady state. When the switch S is closed, the heat generated in the circuit will be:

$\frac{ε^{2} C}{2}$

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$2 ε^{2} C$

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$\frac{3 ε^{2} C}{2}$

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zero

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Solution

The correct option is D
zero

As switch is closed potential difference across capacitor is still 'E' $V_{A} - V_{B} = E$

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Initially the circuit is in steady state. When the switch S is closed, the heat generated in the circuit will be:

The correct option is D zero As switch is closed potential difference across capacitor is still 'E' VA−VB=E

The correct option is D
zero

As switch is closed potential difference across capacitor is still 'E' $V_{A} - V_{B} = E$