Inside a lift, the apparent weight of a man is more than his actual weight. Then the lift is

Moving upward with constant velocity

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Accelerating upward

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Accelerating downward

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Moving downward with constant velocity

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Solution

The correct option is B Accelerating upward
Apparent weight of the body in a lift accelerating upward with acceleration a is m (g + a) therefore the weight feels more than what it is in side a lift accelerating upwards.

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List I	List II
a) Lift is moving up with acceleration a	e) Apparent weight is greater than true weight
b) Lift is moving down with acceleration a	f) Apparent weight is zero
c) Lift is moving with uniformly velocity	g) Apparent weight is equal to true weight
d) Lift is freely falling	h) Apparent weight is less than true weight

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