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Question

10exx2e2xdx

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Solution

I=10(exx2e2x)dx
By integrating by parts

I=10exx2dx10exdx
I=[ex(x2)]1010(2x)exdx10exdx
I=e1(1)0[(2x)ex]10+102exdx10exdx
I=e2e+2e2e012[e2e0]0
I=e2e22+12

I=ee2232

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