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B
sin 2xIn (tan x) + 2x + C
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C
sin xIn (tan x) – x + C
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D
none of these
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Solution
The correct option is A sin 2x In (tan x) – 2x + C We have I=In(tanx)∫2 cos 2xdx −∫sin2x.sec2xtanxdx = sin 2 x In(tan x) −∫2dx = sin 2x In (tan x) - 2x + C