Question

$\int \frac{2-3\sin x}{{\cos }^{2}x}dx$

Answer 1

$\int \frac{2-3\sin x}{{\cos }^{2}x}dx$

$=\int (2{\sec }^{2}x-3\tan x\sec x)dx$

$=2\int {\sec }^{2}xdx-3\int \tan x\sec xdx$

$=2\tan x-3\sec x+c$