Question
\(\int \dfrac{dx}{\sqrt{9x - 4x^2}}\) equals:
\( (A) \dfrac{1}{9} \sin^{-1} \left(\dfrac{9x -8}{8} \right ) + C\)
\( (B) \dfrac{1}{2} \sin^{-1} \left(\dfrac{8x - 9}{9} \right ) + C\)
\((C) \dfrac{1}{3} \sin^{-1} \left(\dfrac{9x - 8}{8} \right ) + C\)
\( (D) \dfrac{1}{2} \sin^{-1} \left(\dfrac{9x -8}{8} \right ) + C\)