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Question

2 sin x(3+sin 2x)dx is equal to



A

12 ln 2+sin xcos x2sin x+cos x12tan1(sin x+cos x2)+C

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B

12 ln 2+sin xcos x2sin x+cos x122tan1(sin x+cos x2)+C

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C

14 ln 2+sin xcos x2sin x+cos x12tan1(sin x+cos x2)+C

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D

None of these

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Solution

The correct option is C

14 ln 2+sin xcos x2sin x+cos x12tan1(sin x+cos x2)+C


2 sin x(3+sin 2x)dx
=sin x+cos x+sin xcos x(3+sin 2x)dx
=sin x+cos x3+sin 2xdxsin x+cos x(3+sin 2x)
= I1+I2
Putting t1=sin xcos x in I1 and t2=sin x+cos x in I2, we get
I=dt1(3+(1t21))dt2(3+(t221))=dt14t21dt22+t22
=14 ln 2+t12t112tan1(t22)+C
=12 ln 2+sin xcos x2sin x+cos x12tan1(sin x+cos x2)+C


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