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Question

Show that sinx(1+sinx)dx=(cosx2+sinx2)dx+dxcos(x/2)+sin(x/2).

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Solution

I=sinx(1+sinx)dx

=(1+sinx)1(1+sinx)dx

=1+sinxdx1(1+sinx)dx

=(cosx2+sinx2)2dxdx(cosx2+sinx2)2

=(cosx2+sinx2)dxdxcosx2+sinx2

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