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Question

cscxlogtanx2dx

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Solution

cscxlog(tanx/2)dx=1sinx(logtanx/2)
=12sinx/2cosx/2×log(tanx/2)
=12tanx/2cos2x/2×log(tanx/2)
Now assume
log(tanx/2)=t
sec2(x/2)2tanx/2dx=dt
dx2cos2(x/2)tanx/2=dt
1tdt=ln(t)+C
=ln(log(tanx/2))


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