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Question

dxx.(inx)(in(inx)).......(ininin....inx)20times is equal to

A
(logloglog.....x)20times+c
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B
(logloglog.....x)19times+c
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C
(logloglog.....x)21times+c
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D
(logloglog.....x)22times+c
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Solution

The correct option is C (logloglog.....x)21times+c

We have,

dxx(lnx)(ln(lnx))........(lnlnlnlnx......lnx)(20times)

Then,

We know that,

dxx=lnx

So, according to given question

dxx(lnx)(ln(lnx))........(lnlnlnlnx......lnx)(20times)

ln(xlnx(ln(lnx))........(lnlnlnlnx.....lnx)20times)

lnlnlnlnx.....lnx(21times)

Hence this is the answer.

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