CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
117
You visited us 117 times! Enjoying our articles? Unlock Full Access!
Question

xx2+1(2lnx+1)dx

Open in App
Solution

Given : xx2+1(2lnx+1)dx
Let :
t=xx2loget=x2logx
Differentiating with respect to x
1tdt=2×lnx+x2×1xdt=xx2+1(2lnx+1)dxxx2+1(2lnx+1)dx=dt=t=xx2+C
Hence the correct answer is xx2+C

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Parts
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon