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Byju's Answer
Standard XII
Mathematics
Inequalities of Integrals
Integral of ...
Question
Integral of
(
2
x
−
3
)
5
+
1
(
7
x
−
5
)
3
+
1
√
(
5
x
−
4
)
+
1
2
−
3
x
+
√
3
x
+
2
is
Open in App
Solution
Say,
I
=
∫
(
(
2
x
−
3
)
5
+
1
(
7
x
−
5
)
3
+
1
√
(
5
x
−
4
)
+
1
2
−
3
x
+
√
3
x
+
2
)
d
x
=
∫
(
2
x
−
3
)
5
d
x
+
∫
1
(
7
x
−
5
)
3
d
x
+
∫
1
√
(
5
x
−
4
)
d
x
+
∫
1
2
−
3
x
d
x
+
∫
√
3
x
+
2
d
x
=
1
2
(
(
2
x
−
3
)
5
+
1
5
+
1
)
+
1
7
(
(
7
x
−
5
)
−
3
+
1
−
3
+
1
)
+
1
5
(
(
5
x
−
4
)
−
1
2
+
1
−
1
2
+
1
)
+
(
−
1
3
(
)
log
(
2
−
3
x
)
+
1
3
(
(
3
x
+
2
)
1
2
+
1
1
2
+
1
)
+
C
⇒
I
=
1
2
(
2
x
−
3
)
6
−
1
14
⋅
1
(
7
x
−
5
)
2
+
2
5
√
5
x
−
4
−
1
3
log
(
2
−
3
x
)
+
2
9
(
3
x
+
2
)
3
/
2
+
C
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0
Similar questions
Q.
Integrate wrt x
1
√
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+
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