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Question

Integral of (2x3)5+1(7x5)3+1(5x4)+123x+3x+2 is

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Solution

Say, I=((2x3)5+1(7x5)3+1(5x4)+123x+3x+2)dx


=(2x3)5dx+1(7x5)3dx+1(5x4)dx+123xdx+3x+2dx

=12((2x3)5+15+1)+17((7x5)3+13+1)+15((5x4)12+112+1)+(13()log(23x)+13((3x+2)12+112+1)+C

I=12(2x3)61141(7x5)2+255x413log(23x)+29(3x+2)3/2+C

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