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Question

exsinx+2cosxsinxdx=


A

excosx+c

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B

exsinx+c

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C

exsin2x+c

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D

exsin2x+c

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E

ex(cosx+sinx)+c

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Solution

The correct option is C

exsin2x+c


Explanation for the correct Option:

Integrating using substitution:

Given

exsinx+2cosxsinxdx=exsin2xdx+2exsinxcosxdx=exsin2xdx+2sinxcosxdx

Let's take fx=sinx2f'x=2sinxcosx

Substituting the values, we get

=exf(x)+f'(x)dx=exf(x)+cexf(x)+f'(x)dx=exf(x)+c=exsin2x+cf(x)=sin2x

Hence, the correct answer is option (C).


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