Question

Integrate the following function: $\sqrt{ax+b}$

Answer 1

$\int \sqrt{ax+b}dx$

$=\int {(ax+b)}^{\frac{1}{2}}dx$

$=\frac{{(ax+b)}^{\frac{1}{2}+1}}{a}+C$

$=\int \frac{{(ax+b)}^{\frac{3}{2}}}{a}+c.$

Hence, the answer is $\int \frac{{(ax+b)}^{\frac{3}{2}}}{a}+c.$