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Question

Integrate the function f(ax+b)[f(ax+b)]n

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Solution

f(ax+b)[f(ax+b)]n
Let f(ax+b)=taf(ax+b)dx=dt
f(ax+b)[f(ax+b)]ndx=1atndt
=1a[tn+1n+1]
=1a(n+1)(f(ax+b))n+1+C

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