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Question

Integrate the function:
f(ax+b)[f(ax+b)]n

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Solution

Let

I= f(ax+b)[f(ax+b)]n dx

Substituting f(ax+b)=t

Differentiating w.r.t. x

f(ax+b).a=dtdx

f(ax+b)dx=dta

Now,

I= tndta=1a tn dt

I=1a[tn+1n+1]+C

I=[f(ax+b)]n+1a(n+1)+C

Where C is constant of integration



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