Internal resistance of a $2.1 V$ cell which gives a current of 0.2 A through an external resistance of $10 Ω$ is

0.2 Ω

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0.5 Ω

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0.8 Ω

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1.0 Ω

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Solution

The correct option is B $0.5 Ω$

$\frac{2. 1}{10 + r} = 0.2$
$2.1 = 2 + 0.2 r$
$0.1 = 0.2 r$
$⟹ r = 0.5 Ω$

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Internal resistance of a 2.1 V cell which gives a current of 0.2 A through an external resistance of 10 Ω is

The correct option is B 0.5 Ω 2.110+r=0.2 2.1=2+0.2r 0.1=0.2r ⟹r=0.5 Ω

Internal resistance of a $2.1 V$ cell which gives a current of 0.2 A through an external resistance of $10 Ω$ is

The correct option is B $0.5 Ω$

$\frac{2. 1}{10 + r} = 0.2$
$2.1 = 2 + 0.2 r$
$0.1 = 0.2 r$
$⟹ r = 0.5 Ω$