Interval containing the value of the integral -15x-1x-2x-3x-4x-5dx

The correct option is A ( π2, π2) [ I=∫ _ 1 ^ 5 ( x 1 ) ( x 2 ) #160; ( x 3 ) ( x 4 ) ( x 5 ) dx→ (i); ∫ _ a ^ b f( ...

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Modulus Function

Interval cont...

Question

Interval containing the value of the integral $\int_{1}^{5} (x - 1) (x - 2) (x - 3) (x - 4) (x - 5) d x$

(- \frac{π}{2}, \frac{π}{2})

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(0, \frac{π}{2})

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(- \frac{π}{2}, 0)

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(\frac{π}{8}, \frac{5 π}{4})

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f (x) = ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ \begin{matrix} x + a^{2} \sqrt{2} s i n x, & 0 \leq x < \frac{π}{4} x c o t x + b, & \frac{π}{4} \leq x < \frac{π}{2} b s i n 2 x - a c o s 2 x, & \frac{π}{2} \leq x \leq π \end{matrix}

[0, π]

If sin^-1x = y then the range of y is:

3 π / 4 \int π / 4 \frac{x}{1 + sin x} d x

tan x > cot x

x \in (0, π) - {\frac{π}{2}}

f (x) = s i n^{- 1} x + 2 t a n^{- 1} x + x^{2} + 4 x + 1

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