Iodine and hypo react to produce :

N a_{2} S

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N a_{2} S O_{3}

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N a_{2} S O_{4}

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N a_{2} S_{4} O_{6}

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Solution

The correct option is C $N a_{2} S_{4} O_{6}$
Iodine and hypo react to produce $N a_{2} S_{4} O_{6}$

$I_{2} + 2 N a_{2} S_{2} O_{3} ⟶ 2 I_{2} + N a_{2} S_{4} O_{6} + 2 N a I$

Hence option D is correct.

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Similar questions

_{4}

H_{2} S O_{4}

N a_{2} C O_{3}, N a H C O_{3}, N a_{2} S O_{3}, N a_{2} S, N a_{2} S_{2} O_{3}, N a_{2} S O_{4}, N a N O_{2}

N a_{2} C O_{3} S O_{2} - - \to (A) N a_{2} C O_{3} - ---- \to (B) S \to (C) A g N O_{3} - --- \to (D)

Iodine reacts with hypo to give:

N a_{2} S_{2} O_{3}

N a_{2} S

S + N a O H \to N a_{2} S_{2} O_{3} + N a_{2} S

N a I

N a_{2} S O_{4}

N a_{2} S_{2} O_{3} + I_{2} + N a O H \to N a I + N a_{2} S O_{4} + H_{2} O

N a I

A g N O_{3}

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