Iodine dissolves in aqueous Kl due to the formation of:

I^{-}

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I_{2}^{-}

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I_{3}^{-}

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I_{4}^{-}

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Solution

The correct option is A $I_{3}^{-}$
$K I (a q) \to K^{(+)} + I^{-}$
$I_{2} + I^{-} \to I_{3}^{-}$
$∴$ Iodine dissolves in KI (aq) due to the formation of $I_{3}^{-}$ ion.

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