Iodine is dissolved in a benzene solution. The mole fraction of Iodine in solution is $0.25$ . Find out the molality of the solution?

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Solution

The mole fraction of Iodine in solution is $0.25$ .
1 mole of solution will have $0.25$ moles of iodine and $1 - 0.25 = 0.75$ moles of benzene. The molecular weight of benzene is $78$ g/mol.
The mass of benzene $= 0.75 m o l \times 78 g / m o l = 58.5 g$
Convert the unit of mass from g to kg.
$58.5 g \times \frac{1 k g}{1000 g} = 0.0585 k g$
The molality of the solution $= \frac{0.25 m o l}{0.0585 k g} = 4.27 m$

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