Question

Ionic product of $H_{2}O$ is ${10}^{-14}$. The $H^{+}$ ion concentration in $0.1M$ $NaOH$ solution is:

• A. ${10}^{-11}M$
• B. ${10}^{-13}M$
• C. ${10}^{-1}M$
• D. ${10}^{-4}M$

Answer 1

The correct option is B ${10}^{-13}M$

Solution:- (B) ${10}^{-13}M$

As we know that,

$K_2=\left[H^{+}\right]\left[{OH}^{-}\right]$

Given:-

$K_w={10}^{-14}$

$\left[{OH}^{-}\right]=0.1={10}^{-1}$

$\therefore \left[H^{+}\right]=\frac{{10}^{-14}}{{10}^{-1}}={10}^{-13}$

Hence the $H^{+}$ ion concentration will be ${10}^{-13}M$.