Ionization energy IE of Na is 513 kJ mol -1- The value in eV molecule -1 is x- 10-1- Then- the value of x is-

513 kJ mol ^ 1 = 513000J / 6.02× 10 ^ 23 molecule ^ 1 = 8.522× 10 ^ 19 J molecule ^ 1 = 8.522× 10 ^ 19 / 1.6× 10 ^ 19 eV=5.326 ...

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Alpha Decay

Ionization en...

Question

Ionization energy (IE) of Na is 513 kJ ${m o l}^{- 1}$ . The value in eV ${m o l e c u l e}^{- 1}$ is $x \times 10^{- 1}$ . Then, the value of x is________.

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