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Electron Gain Enthalpy

Ionization en...

Question

Ionization enthalpy of $F = 320 k J m o l^{- 1}$ . The electron gain enthalpy of flourine would be:

A

- 320 k J m o l^{- 1}

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B

- 160 k J m o l^{- 1}

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C

320 k J m o l^{- 1}

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D

160 k J m o l^{- 1}

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Solution

The correct option is B $- 320 k J m o l^{- 1}$
The electron gain enthalpy is $= - 320$ $k J / m o l^{- 1}$
Since, I.P and E.A are equal in magnitude but opposite direction.

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