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Question

IP1 and IP2 of Mg are 178 and 348 k cal mol1. The energy required for the reaction Mg Mg2+ + 2e is


A

178 kcal.

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B

526 kcal .

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C

348 kcal .

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D

180 kcal .

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Solution

The correct option is B

526 kcal .


IP1 = 178 K cal mol1

IP2 = 348 K cal mol1

Now, take a look at the reaction

Mg Mg2+ + 2e

So, to take out two electrons from Mg, we have to provide energy.

Therefore, total energy required will be

= IP1 + IP2

= 178 + 348

= + 526 k. cal


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