Question

Iron forms halide salts by reacting the metal directly with halogen. $Fe{I}_3$ does not exist. $Fe{F}_3$ is white solid inspite of five unpaired electrons with $d^5$ congfiguration. $Fe{Cl}_3$ is soluble in water and is used as a mordant in dyeing industry.

Anhydrous $Fe{Cl}_3$ can be prepared by reaction of:

• A. $Fe$ with dry chlorine
• B. $Fe$ with dil. HCl in the presence of $O_2$
• C. $Fe(OH{)}_3$ with conc. $HCl$
• D. ${Fe}_2{O}_3$ with conc. $HCl$

Answer 1

The correct option is A $Fe$ with dry chlorine

Anhydrous $FeC{l}_3$ can be prepared by reaction of Fe with dry chlorine.
$2Fe+3C{l}_2\left(dry\right)\to heat2FeC{l}_3$