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Question

Iron (III) oxide is formed according to the following balanced chemical equation:
4Fe(g)+3O2(g)2Fe2O3(g)
The reaction of 8.0 moles of solid iron with 9.0 moles of oxygen gas produces :

A
4.0 moles of Fe2O3 and 3.0 moles excess O2
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B
4.0 moles of Fe2O3 and 6.0 moles excess O2
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C
6.0 moles of Fe2O3 and 2.0 moles excess O2
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D
6.0 moles of Fe2O3 and 3.0 moles excess O2
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E
6.0 moles of Fe2O3 and 4.0 moles excess O2
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Solution

The correct option is A 4.0 moles of Fe2O3 and 3.0 moles excess O2
The balanced chemical equation is
4Fe(g)+3O2(g)2Fe2O3(g)
Thus, 4 moles of Fe reacts with 3 moles of oxygen to form 2 moles of ferric oxide.
So 8 moles of Fe will react with 3×84=6 moles of oxygen to form 2×84=4 moles of ferric oxide.
9.06=3.0 moles of oxygen will remain as excess.

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