Iron reacts with oxygen to form $F e_{2} O_{3}$ . If the atomic mass of iron is 56, the mass of oxygen that reacts with 2.5 moles of iron is

60.0g

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48.0g

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30.0g

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90.0g

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Solution

The correct option is A
60.0g

$4 F e + 3 O_{2} \to 2 F e_{2} O_{3}$

$4 m o l e o f F e (4 \times 56 = 224 g) r e a c t s w i t h \to 3 m o l e O_{2} (3 \times 32 = 96 g)$

$2.5 m o l e o f F e (2.5 \times 56 = 140 g) r e a c t s w i t h \to \frac{140}{224} \times 96 = 60 g o f O_{2}$

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