Iron reacts with oxygen to form Fe₂O₃. If the atomic mass of iron is 56, the mass of oxygen that reacts with 2.5moles of iron is

30.0g

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60.0g

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90.0g

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448.0g

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Solution

The correct option is B
60.0g

$4 F e + 3 O_{2} \to 2 F e_{2} O_{3} 4 m o l e o f F e (4 \times 56 = 224 g) r e a c t w i t h \to 3 m o l e O_{2} (3 \times 32 = 96 g) 2.5 m o l e o f F e (2.5 \times 56 = 140 g) r e a c t s w t i h \to \frac{140}{224} \times 96 = 60 g o f O_{2}$

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Similar questions

Iron reacts with oxygen to form $F e_{2} O_{3}$ . If the atomic mass of iron is 56, the mass of oxygen that reacts with 2.5 moles of iron is

I

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I I

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{Fe}_{2} O_{3}

{Fe}_{2} O_{3}

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