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Byju's Answer
Standard XII
Mathematics
Parametric Differentiation
Is LHS=RHS? ...
Question
Is LHS=RHS?
√
c
o
s
e
c
θ
−
1
c
o
s
e
c
θ
+
1
+
√
c
o
s
e
c
θ
+
1
c
o
s
e
c
θ
−
1
=
2
cos
θ
Say true or false?
A
True
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B
False
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C
Ambiguous
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D
Data insufficient
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Solution
The correct option is
B
False
Simplifying the given expression, we get
c
o
s
e
c
θ
−
1
+
c
o
s
e
c
θ
+
1
√
c
o
s
e
c
2
θ
−
1
=
2
c
o
s
e
c
θ
c
o
t
θ
=
2
c
o
s
e
c
θ
c
o
s
θ
.
c
o
s
e
c
θ
=
2
c
o
s
θ
=
2
s
e
c
θ
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0
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