is not a factor of $x^{3} - x$ .

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x - 1

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x + 1

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x^{2}

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Solution

The correct option is D $x^{2}$
$x^{3} - x$ can be written as

$x^{3} - x$ = $x (x^{2} - 1)$
$x^{3} - x$ = $x (x - 1) (x + 1)$
So, x, x-1 and x+1 are the factors of $x^{3} - x$

Suggest Corrections

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