CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

is particle is moving with a velocity V=3i+4j at an instant of time if a force F= 4i+6j+5K acts on the particle at that instant then the radius of curvature of the particle is (mass is 2kg)

Join BYJU'S Learning Program
CrossIcon