Is the electron configuration for an element that reacts exothermically with water to produce an alkaline solution and hydrogen gas

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2}

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1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4}

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1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}

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1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}

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1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}

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Solution

The correct option is E $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}$
Option E is the correct answer. The element here is Potassium or $K$ . Potassium reacts vigorously with water to produce Potassium Hydroxide or $K O H$ . This makes the solution alkaline. Along with this Hydrogen gas is also formed.

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Similar questions

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2}

A

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

B

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4}

A

B

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4}

H_{2} X

3 s^{2} 3 p^{4}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5} 4 s^{2}

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