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Byju's Answer
Standard IX
Mathematics
By Grouping
is the factor...
Question
is the factorization of
(
x
y
+
x
+
4
y
+
4
)
.
A
(
x
+
4
)
(
4
y
+
1
)
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B
(
4
x
+
4
)
(
4
y
+
4
)
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C
(
3
x
+
4
)
(
y
+
1
)
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D
(
x
+
4
)
(
y
+
1
)
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Solution
The correct option is
D
(
x
+
4
)
(
y
+
1
)
Given expression:
(
x
y
+
x
+
4
y
+
4
)
By grouping the terms we get,
(
x
y
+
x
+
4
y
+
4
)
=
(
x
y
+
x
)
+
(
4
y
+
4
)
=
x
(
y
+
1
)
+
4
(
y
+
1
)
=
(
y
+
1
)
(
x
+
4
)
So,
(
x
y
+
x
+
4
y
+
4
)
=
(
x
+
4
)
(
y
+
1
)
Suggest Corrections
0
Similar questions
Q.
The mirror image of
y
2
=
4
x
about the line
x
−
y
+
1
=
0
is
Q.
The equation of the conic with focus at (1, −1) directrix along x − y + 1 = 0 and eccentricity
2
is
(a) xy = 1
(b) 2xy + 4x − 4y − 1= 0
(c) x
2
− y
2
= 1
(d) 2xy − 4x + 4y + 1 = 0
Q.
The factors of x
2
+ 4y
2
+ 4y − 4xy − 2x − 8 are
(a) (x − 2y −4) (x − 2y + 2)
(b) (x − y + 2) (x − 4y − 4)
(c) (x + 2y − 4) (x + 2y + 2)
(d) none of these