___is the length of EF, if AB =5cm and CA= 7cm, given that AD is the line of symmetry for the figure.

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Solution

Since AD is the line of symmetry, the part of the figure to the right of this line is same as the part of the figure to the left of it. Therefore, AB= AE=5cm, and CA= FA = 7cm.Hence EF= FA -AE i.e. EF= 7-5= 2cm.

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