Question

is the probability that two friends have different birthdays in a normal year?

• A. $\frac{2}{365}$
• B. $\frac{1}{365}$
• C. $\frac{364}{365}$

Answer 1

The correct option is C $\frac{364}{365}$

Number of days in a year = 365
Therefore, total possible outcomes = 365

If their birthday was on the same day then no. of favorable outcomes =1

Then, required Probability would have been = $\frac{1}{365}$

Hence, the probability that two friends have different birthdays = 1 – $\frac{1}{365}=\frac{364}{365}$