Question

Is there any change in the hybridisation of B and N atoms as a result of the following reaction?

$B{F}_3+N{H}_3\to F_{3}B.N{H}_3$

Answer 1

Boron atom in $B{F}_3$ is $s{p}^2$ hybridized. The orbital picture of boron in the excited state can
be shown as:

Nitrogen atom in $N{H}_3$ is $s{p}^3$ hybridized. The orbital picture of nitrogen can be represented as:

After the reaction has occurred, an adduct $F_{3}B.N{H}_3$ is formed as hybridization of ‘B’ changes to $s{p}^3$ . However, the hybridization of ‘N’ remains intact.