Question

Is there any change in the hybridisation of $B$ and $N$ atoms as a result of the following reaction?

$B{F}_3+N{H}_3\to [F_{3}B.N{H}_3]$

Answer 1

${}^{s{p}^2}B{F}_3+N{H}_3\to F-\underset{\underset{F}{|}}{\stackrel{\stackrel{F}{|}}{B^{s{p}^3}}}\leftarrow \underset{\underset{H}{|}}{\stackrel{\stackrel{H}{|}}{N}}-H$

The hybridization of B changes from $s{p}^2$ to $s{p}^3$ whereas the hybridization of N remains same i.e $s{p}^3$.