Question

__________ is true for the discriminant of a quadratic equation $x^2+x+1=0$.

• A. $D=0$
• B. $D<0$
• C. $D>0$
• D. $D$ is a perfect square

Answer 1

Answer: (B)

$D<0$

$x^2+x+1=0$
Here, $a=1,b=1,c=1$
Discriminant $D=b^2-4ac$
$=(1{)}^2-4(1\left)\right(1)$
$=1-4$
$=-3<0$
$\therefore D<0$ is true