Step : Finding the solution of equation 2x2−7x+9=0:
For x = -3 to be solution of the given quadratic equation it should satisfy the given equation,
2x2−7x+9=0
Substituting x =-3 in the given equation,
We get,
L.H.S=2(−3)2−7(−3)+9
=18+21+9
=48
≠R.H.S
Hence, x = -3 is not a solutioin of the given quadratic equation 2x2−7x+9=0