Question

It costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel of 10 m deep. If the cost of painting is at the rate of $Rs20per{m}^2$, find the inner curved surface area of the vessel.

$[Assume\pi =\frac{22}{7}]$

• A. $410m^2$
• B. $190m^2$
• C. $210m^2$
• D. $110m^2$

Answer 1

The correct option is D

$110m^2$

Rs. 20 is the cost of painting $1m^2$ area.

Area painted for Rs. 2200 $=(\frac{1}{20}\times 2200)m^2$

$=110m^2$

Therefore, the inner surface area of the vessel is $110m^2$.