Question

It $\frac{\sin \theta }{1-\cos \theta }+\frac{\sin \theta }{1+\cos \theta }$ $=4(0<0<90)$ then find value of $\theta$

Answer 1

$\frac{\sin \theta }{1-\cos \theta }+\frac{\sin \theta }{1+\cos \theta }=4$

$⟹\sin \theta (\frac{1}{1-\cos \theta }+\frac{1}{1+\cos \theta })=4$

$⟹\sin \theta (\frac{1+\cos \theta +1-\cos \theta }{1-{\cos }^2\theta })$

$⟹\sin \theta \times \frac{2}{{\sin }^2\theta }=4$

$⟹\sin \theta =\frac{1}{2}$

$⟹\theta ={30}^{\circ }$