Question

It is known that a box of 200 electric bulbs contains 16 defective bulbs. One bulb is taken out at random from the box. What is the probability that the bulb drawn is (i) defective, (ii) nondefective?

Answer 1

no. of bulbs = 200
no. of defective bulbs = 16
no. of correct or nondefective bulbs = 200 - 16 = 184

(i) The probability of getting defective bulb = $\frac{16}{200}=\frac{2}{25}$

(ii) The probability of getting nondefective bulb = $\frac{184}{200}=\frac{23}{25}$