Question

It is known that a box of 200 electric bulbs contains 16 defective bulbs. One bulb is taken out at random from the box. What is the probability that the bulb drawn is
(i) defective
(ii) non-defective

Answer 1

Total number of possible outcomes = 200

(i) Number of defective bulbs = 16
∴ P(getting a defective bulb) = $\frac{16}{200}=\frac{2}{25}$

(ii) Number of non-defective bulbs = 200 − 16 = 184
∴ P(getting a non-defective bulb) = $\frac{184}{200}=\frac{23}{25}$