It is known that a box of 600 electric bulbs contains 12 defective bulbs. One bulb is taken out at random from this box. What is the probability that it is a non-defective bulb?

$\frac{588}{600}$

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$\frac{12}{600}$

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0.94

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0.98

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Solution

The correct option is D
0.98

Number of non-defective bulbs = 600 – 12 = 588

Total number of bulbs = 600

Probability of picking a non-defective bulb $= \frac{Number of non-defective bulbs}{Total number of bulbs}$

Probability of picking a non-defective bulb = $\frac{588}{600}$ = 0.98

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It is known that a box of 600 electric bulbs contains 12 defective bulbs. One bulb is taken out at random from this box. What is the probability that it is a non-defective bulb?

The correct option is D 0.98 Number of non-defective bulbs = 600 – 12 = 588 Total number of bulbs = 600 Probability of picking a non-defective bulb =Number of non-defective bulbsTotal number of bulbs Probability of picking a non-defective bulb = 588600 = 0.98

The correct option is D
0.98

Number of non-defective bulbs = 600 – 12 = 588

Total number of bulbs = 600

Probability of picking a non-defective bulb $= \frac{Number of non-defective bulbs}{Total number of bulbs}$

Probability of picking a non-defective bulb = $\frac{588}{600}$ = 0.98