It is known that a box of 800 electric bulbs contains 36 defective bulbs. One bulb is taken at random out of the box. What is the probability that the bulb chosen is non-defective?

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Solution

Total number of bulbs in the box = 800
Number of defective bulbs = 36
Number of non-defective bulbs = 800 − 36 = 764
Let E be the event that the chosen bulb is non-defective.

∴ Required probability = P(E) = $\frac{764}{800} = \frac{191}{200}$ 4880 = 35

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It is known that a box of 800 electric bulbs contains 36 defective bulbs. One bulb is taken at random out of the box. What is the probability that the bulb chosen is non-defective?

Total number of bulbs in the box = 800 Number of defective bulbs = 36 Number of non-defective bulbs = 800 − 36 = 764 Let E be the event that the chosen bulb is non-defective. ∴ Required probability = P(E) = 764800 =191200 4880 = 35

Total number of bulbs in the box = 800
Number of defective bulbs = 36
Number of non-defective bulbs = 800 − 36 = 764
Let E be the event that the chosen bulb is non-defective.

∴ Required probability = P(E) = $\frac{764}{800} = \frac{191}{200}$ 4880 = 35