It is said that on heating gypsum at 373 K, CaSO4.2H2O loses water to form CaSO4.1/2H2O. But why is it still holding 1/2 molecule of water still?

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Solution

On heating gypsum water is removed to form Plaster of Paris , which has formula CaSO₄.1/2H₂O in which the water molecule is attached as water of crystallisation. In actual, one water molecule is attached to 2 molecules to CaSO₄ i.e. it is represented as (CaSO₄)₂.H₂O .

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Q. Gypsum is a widely occurring mineral. It is the sulphate of calcium with two molecules of water attached. On heating it loses three-quarters of its water and becomes:

Q. On heating gypsum at 373 K, it loses water molecules and becomes ‘X’. Number of water molecules present in one formula unit of ‘X’ is

373 K पर जिप्सम को गर्म करने पर यह जल के अणुओं का त्याग कर देता है तथा ‘X’ बन जाता है। ‘X’ की एक सूत्र इकाई में उपस्थित जल के अणुओं की संख्या है

Q. Is there any difference btw the uses of

C a S O_{4} .2 H_{2} O

C a S O_{4} . \frac{1}{2} H_{2} O

Q. Gypsum,

C a S O_{4} .2 H_{2} O

, on heating to about

120^{0} C

forms a compound which has the chemical composition represented by

$\begin{matrix} List I & List II 1. Plaster of Paris & a. C a S O_{4} .2 H_{2} O 2. Epsomite & b. C a S O_{4} .1 / 2 H_{2} O 3. Kieserite & c. M g S O_{4} .7 H_{2} O 4. Gypsum & d. M g S O_{4} . H_{2} O e. C a S O_{4} \end{matrix}$

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It is said that on heating gypsum at 373 K, CaSO4.2H2O loses water to form CaSO4.1/2H2O. But why is it still holding 1/2 molecule of water still?

On heating gypsum water is removed to form Plaster of Paris , which has formula CaSO4.1/2H2O in which the water molecule is attached as water of crystallisation. In actual, one water molecule is attached to 2 molecules to CaSO​4 i.e. it is represented as (CaSO4)2.H2O .

On heating gypsum water is removed to form Plaster of Paris , which has formula CaSO₄.1/2H₂O in which the water molecule is attached as water of crystallisation. In actual, one water molecule is attached to 2 molecules to CaSO₄ i.e. it is represented as (CaSO₄)₂.H₂O .