Question

IUPAC name of CH3(CH2)3CH3 is .

• A. Pentane
• B. Propane
• C. Butane

Answer 1

The correct option is A Pentane

What should we do first?
Let's calculate the number of carbons present.
For that, let's write it in a clearer format using the bonds.

$H-\underset{H}{\underset{|}{\stackrel{H}{\stackrel{|}{C}}}}-\underset{H}{\underset{|}{\stackrel{H}{\stackrel{|}{C}}}}-\underset{H}{\underset{|}{\stackrel{H}{\stackrel{|}{C}}}}-\underset{H}{\underset{|}{\stackrel{H}{\stackrel{|}{C}}}}-\underset{H}{\underset{|}{\stackrel{H}{\stackrel{|}{C}}}}-H$

Now, five carbons are present
Only single bonds are present
Five carbon $\Rightarrow$ word root $\to$ pent
single bonds $\Rightarrow$ suffix $\to$ ane
Therefore, it is pentane.