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Question

IUPAC nomenclature of

H3C−CH3|C|CH3−CH=CH3|C−CH3

A
2,4,4 - trimethylpent -2-ene
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B
2,4,4 - trimethylpent -3-ene
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C
2,2,4 - trimethylpent -3-ene
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D
2,2,4 - trimethylpent -2-ene
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Solution

The correct option is B 2,4,4 - trimethylpent -2-ene
According to IUPAC,
a. The longest chain contains total 5 carbon atoms so the root word must be "pent".
b. Double bond gets higher priority than the alkyl group. So the numbering should be done in such a way that the double bonded carbons get lower number. There are two methyl groups at the C4 and one methyl group at the C2. So the name of thr compound will be 2,4,4-trimethylpent-2-ene. So the correct answer is A

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